ABE TUTORIALS

AGRICULTURAL AND BIOSYSTEMS ENGINEERING

PROBLEM:
DETERMINE THE FIELD CAPACITY IN HA/HR FOR A DISC HARROW HAVING A DIAMETER OF 609.7 MM AND THERE ARE 20 DISCS IN A GANG. THE TOTAL WIDTH OF CUT IS 2,286 MM. THE HARROWING SPEED IS 3.5 KPH. THE FIELD EFFICIENCY IS 77%.

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1. Select the field capacity (ha/hr):

a. 0.62
b. 0.81
c. 3286
d. 4267

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Step 1: Identify given parameters.
Width (W) = 2,286 mm = 2.286 m
Speed (S) = 3.5 kph
Efficiency (Ef) = 0.77

Step 2: Apply the Capacity formula.
Actual Field Capacity (AFC) = (W × S × Ef) / 10
AFC = (2.286 × 3.5 × 0.77) / 10
AFC = 6.16077 / 10 ≈ 0.616 ha/hr

Result: a. 0.62 (rounded)

2. Assuming an 8-hr working day, how many days would the above machine finish a 100 hectare land?

a. 100
b. 20
c. 161
d. 26

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Step 1: Calculate capacity per day.
Capacity per day = AFC × 8 hours
Capacity per day = 0.616 ha/hr × 8 hr = 4.928 hectares/day

Step 2: Calculate total days needed.
Total Days = Total Area / Capacity per day
Total Days = 100 ha / 4.928 ha/day ≈ 20.29 days

Result: b. 20